$$\text { Let } p \text { represent } 7

Question

$$\text { Let } p \text { represent } 7 < 8 \text {, } q \text { represent } 2 < 5 < 6 \text {, and } \mathbf { r } \text { represent } 3 < 2 \text {. Decide whether the statement is true or false. }$$
-$\sim q \wedge \sim r$

Quizplus · Accepted Answer

The statement $q$ is true because $2 < 5 < 6$ is a true statement, making $\sim q$ (not $q$) false. The statement $r$ is false because $3 < 2$ is false, making $\sim r$ (not $r$) true. Therefore, $\sim q \wedge \sim r$ is false AND true, which evaluates to false. However, the question asks to decide whether the statement is true or false without specifying what "the statement" refers to in terms of its truth value evaluation. Given the logical operations, the evaluation of $\sim q \wedge \sim r$ is false, but since the question's phrasing might imply asking about the correctness of the process (which was accurately described), there's a misunderstanding in my explanation. The correct interpretation of the task should lead to the evaluation of $\sim q \wedge \sim r$ as false, based on the logical operations applied to the truth values of $q$ and $r$.

- ∼q∧∼r\sim q \wedge \sim r∼q∧∼r

- $\sim q \wedge \sim r$