When using a truth table, the statement $\mathrm { q } \rightarrow \mathrm { p }$ is equivalent to $\sim \mathrm { q } \vee \mathrm { p }$ .

Question

When using a truth table, the statement $\mathrm { q } \rightarrow \mathrm { p }$ is equivalent to $\sim \mathrm { q } \vee \mathrm { p }$.

Quizplus · Accepted Answer

The implication $\mathrm { q } \rightarrow \mathrm { p }$ is logically equivalent to $\sim \mathrm { q } \vee \mathrm { p }$ because both express that if $\mathrm { q }$ is true, then $\mathrm { p }$ must also be true, or else if $\mathrm { q }$ is false, the statement is true regardless of $\mathrm { p }$'s truth value.

When Using a Truth Table, the Statement q→p\mathrm { q } \rightarrow \mathrm { p }q→p

When Using a Truth Table, the Statement $\mathrm { q } \rightarrow \mathrm { p }$