A $( 1 - \alpha )$-level confidence interval for a population proportion that has a margin of error of at most $E$ can be obtained by choosing $\mathrm { n } = 0.25 \left( \frac { \mathrm { z } _ { \alpha / 2 } } { \mathrm { E } } \right) ^ { 2 }$ rounded up to the nearest whole number. Explain why, if $\hat { p }$ is not equal to $0.5$, this will result in a larger sample size than needed to obtain the required margin of error.

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The Answer of A $( 1 - \alpha )$-level confidence interval for a population proportion that has a margin of error of at most $E$ can be obtained by choosing $\mathrm { n } = 0.25 \left( \frac { \mathrm { z } _ { \alpha / 2 } } { \mathrm { E } } \right) ^ { 2 }$ rounded up to the nearest whole number. Explain why, if $\hat { p }$ is not equal to $0.5$, this will result in a larger sample size than needed to obtain the required margin of error.

A (1−α)( 1 - \alpha )(1−α) -Level Confidence Interval for a Population Proportion That Has a a Population

A $( 1 - \alpha )$ -Level Confidence Interval for a Population Proportion That Has a a Population