$\mathrm { F } _ { 0.99 }$ for an $\mathrm { F }$-curve with $\mathrm { df } = ( 25,26 )$ is equal to $1 / \mathrm { F } _ { 0.01 }$ for an $\mathrm { F }$-curve with $\mathrm { df } = ( 26,25 )$.

Question

Quizplus · Accepted Answer

The relationship between the F-distribution and its critical values is such that $\mathrm { F } _ { \alpha }$ for a given $\mathrm { F }$-curve with degrees of freedom $(d_1, d_2)$ is the reciprocal of $\mathrm { F } _ { 1-\alpha }$ for an $\mathrm { F }$-curve with degrees of freedom swapped $(d_2, d_1)$. Thus, $\mathrm { F } _ { 0.99 }$ with $\mathrm { df } = ( 25,26 )$ is indeed equal to $1 / \mathrm { F } _ { 0.01 }$ with $\mathrm { df } = ( 26,25 )$.

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$\mathrm { F } _ { 0.99 }$ For An $\mathrm { F }$