Solve the problem.
-Find the dimensions of a rectangular garden with perimeter $62 \mathrm { yd }$ and area $220 \mathrm { yd } ^ { 2 }$.
A) $20 \mathrm { yd }$ by $22 \mathrm { yd }$
B) $20 \mathrm { yd }$ by $11 \mathrm { yd }$
C) $10 \mathrm { yd }$ by $11 \mathrm { yd }$
D) $10 \mathrm { yd }$ by $22 \mathrm { yd }$

Question

Quizplus · Accepted Answer

The perimeter equation is $2(l + w) = 62$, simplifying to $l + w = 31$. The area equation is $l \times w = 220$. Solving these simultaneously, $l = 20$ and $w = 11$ satisfy both equations.

Solve the Problem 62yd62 \mathrm { yd }62yd And Area 220yd2220 \mathrm { yd } ^ { 2 }220yd2

Solve the Problem $62 \mathrm { yd }$ And Area $220 \mathrm { yd } ^ { 2 }$