Solve the problem.
-Given $A = \left[ \begin{array} { r r } 3 & - 1 \ - 2 & - 5 \end{array} \right]$, find $A ^ { 3 }$.
A)
$\left[ \begin{array} { r r } 5 & - 47 \ - 94 & - 99 \end{array} \right]$
B)
$\left[ \begin{array} { r r } 27 & - 1 \ - 8 & - 125 \end{array} \right]$
C)
$\left[ \begin{array} { r r } 29 & - 21 \ - 42 & - 139 \end{array} \right]$
D)
$\left[ \begin{array} { r r } 31 & - 15 \ - 38 & 91 \end{array} \right]$

Question

Quizplus · Accepted Answer

To find $A^3$, we first compute $A^2 = A \times A$, then multiply the result by $A$ again. The correct calculation leads to the matrix in option C.

Solve the Problem A=[3−1−2−5]A = \left[ \begin{array} { r r } 3 & - 1 \\ - 2 & - 5 \end{array} \right]A=[3−2​−1−5​]

Solve the Problem $A = \left[ \begin{array} { r r } 3 & - 1 \\ - 2 & - 5 \end{array} \right]$