Solve for the indicated variable.
-$\mathrm { I } = \mathrm { I } _ { 0 } \mathrm { e } ^ { \mathrm { kt } / 900 }$, for $\mathrm { t }$
A) $\mathrm { t } = \frac { 900 } { \mathrm { k } } \ln \left( \mathrm { I } - \mathrm { I } _ { 0 } \right)$
B) $t = \frac { 900 I } { \mathrm { kI } _ { 0 } }$
C) $t = \frac { k } { 900 } \ln \frac { \mathrm { I } } { \mathrm { I } _ { 0 } }$
D) $t = \frac { 900 } { k } \ln \frac { \mathrm { I } } { \mathrm { I } _ { 0 } }$

Question

Quizplus · Accepted Answer

To solve for $t$, divide both sides by $I_0$, then take the natural logarithm of both sides, and finally solve for $t$ to get $t = \frac { 900 } { k } \ln \frac { \mathrm { I } } { \mathrm { I } _ { 0 } }$.

Solve for the Indicated Variable I=I0ekt/900\mathrm { I } = \mathrm { I } _ { 0 } \mathrm { e } ^ { \mathrm { kt } / 900 }I=I0​ekt/900

Solve for the Indicated Variable $\mathrm { I } = \mathrm { I } _ { 0 } \mathrm { e } ^ { \mathrm { kt } / 900 }$