Solve the problem.
-The length of a rectangle is 4 inches more than its width. If 2 inches are taken from the length and added to the width, the figure becomes a square with an area of 144 square inches. What are the dimensions of the original figure?
A) $10 \mathrm { in. }$ by $14 \mathrm { in }$.
B) $10 \mathrm { in. }$ by $12 \mathrm { in }$.
C) 12 in. by 12 in.
D) $8 \mathrm { in. }$ by $12 \mathrm { in }$.

Question

Quizplus · Accepted Answer

The square formed has sides of 12 inches (since $12 \times 12 = 144$). Originally, 2 inches were added to the width and taken from the length to form this square, so the original width was 10 inches and the length was 14 inches.

Solve the Problem 10in.10 \mathrm { in. }10in. By 14in14 \mathrm { in }14in

Solve the Problem $10 \mathrm { in. }$ By $14 \mathrm { in }$