Use Descartesʹ Rule of Signs to determine the possible number of positive real zeros and the possible negative real zeros for the function.
-$$- 3 x ^ { 4 } - 2 x ^ { 3 } - 6 x ^ { 2 } - 4 x + 2 = 0$$
A) Positive $( 2,0 )$, negative $( 2,0 )$
B) Positive (1), negative (1)
C) Positive (1), negative $( 3,1 )$
D) Positive (1), negative (2)

Question

Quizplus · Accepted Answer

The function has one sign change for positive zeros and three sign changes for negative zeros, indicating 1 positive zero and either 3 or 1 negative zeros.

Use Descartesʹ Rule of Signs to Determine the Possible Number −3x4−2x3−6x2−4x+2=0- 3 x ^ { 4 } - 2 x ^ { 3 } - 6 x ^ { 2 } - 4 x + 2 = 0−3x4−2x3−6x2−4x+2=0

Use Descartesʹ Rule of Signs to Determine the Possible Number $- 3 x ^ { 4 } - 2 x ^ { 3 } - 6 x ^ { 2 } - 4 x + 2 = 0$