Solve the problem.
-If an object is thrown upward with an initial velocity of $11 \mathrm { ft }$ per second, then its height is given by $h = - 11 t ^ { 2 } + 44 t$. What is its maximum height?
A) $44 \mathrm { ft }$
B) $33 \mathrm { ft }$
C) $66 \mathrm { ft }$
D) $22 \mathrm { ft }$

Question

Quizplus · Accepted Answer

The maximum height is reached when the velocity is zero. To find the time when the velocity is zero, we solve the equation $v = - 22 t + 44 = 0$. This gives $t = 2$. Substituting this value of $t$ into the equation for height, we get $h = - 11 (2) ^ { 2 } + 44 (2) = 44$.

Solve the Problem 11ft11 \mathrm { ft }11ft Per Second, Then Its Height Is Given By

Solve the Problem $11 \mathrm { ft }$ Per Second, Then Its Height Is Given By