Divide.
-$$\frac { x ^ { 2 } + 14 x + 49 } { x + 7 }$$
A) $x ^ { 2 } + 7$
B) $x - 42$
C) $x ^ { 3 } - 42$
D) $x + 7$

Name: Divide. -\[\frac { x ^ { 2 } + 14 x + 49 } { x + 7 }\] A) $x ^ { 2 } + 7$ B) $x - 42$ C) $x ^ { 3 } - 42$ D) $x + 7$
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Question

Quizplus · Accepted Answer

The numerator $x^2 + 14x + 49$ is a perfect square trinomial, factoring to $(x + 7)^2$. Dividing this by $x + 7$ simplifies to $x + 7$.

Divide - x2+14x+49x+7\frac { x ^ { 2 } + 14 x + 49 } { x + 7 }x+7x2+14x+49​

Divide
- $\frac { x ^ { 2 } + 14 x + 49 } { x + 7 }$