A discrete random variable x can assume five possible values: 2, 3, 5, 8, 10. Its probability distribution is shown below. Find the probability that the random variable x is a value greater
Than 5. $$\begin{array} { c | c c c c c }
\mathrm { x } & 2 & 3 & 5 & 8 & 10 \
\hline p ( x ) & 0.10 & 0.20 & 0.30 & 0.30 & 0.10
\end{array}$$
A)0.60
B)0.70
C)0.40
D)0.30

Question

A discrete random variable x can assume five possible values: 2, 3, 5, 8, 10. Its probability distribution is shown below. Find the probability that the random variable x is a value greater
Than 5. $$\begin{array} { c | c c c c c } 
\mathrm { x } & 2 & 3 & 5 & 8 & 10 \
\hline p ( x ) & 0.10 & 0.20 & 0.30 & 0.30 & 0.10
\end{array}$$
A)0.60
B)0.70
C)0.40
D)0.30

Quizplus · Accepted Answer

The probability that x is greater than 5 is the sum of the probabilities of x being 8 or 10, which is 0.30 + 0.10 = 0.40.

A Discrete Random Variable X Can Assume Five Possible Values x235810p(x)0.100.200.300.300.10\begin{array} { c | c c c c c } \mathrm { x } & 2 & 3 & 5 & 8 & 10 \\\hline p ( x ) & 0.10 & 0.20 & 0.30 & 0.30 & 0.10\end{array}xp(x)​20.10​30.20​50.30​80.30​100.10​​

A Discrete Random Variable X Can Assume Five Possible Values $\begin{array} { c | c c c c c } \mathrm { x } & 2 & 3 & 5 & 8 & 10 \\\hline p ( x ) & 0.10 & 0.20 & 0.30 & 0.30 & 0.10\end{array}$