If y varies directly as x, find the direct variation equation for the situation.
-$y = 2 \text { when } x = \frac { 1 } { 3 }$
A) $y = \frac { 1 } { 2 } x$
B) $y = 6 x$
C) $y = x + \frac { 5 } { 3 }$
D) $y = \frac { 1 } { 6 } x$

Question

Quizplus · Accepted Answer

The direct variation equation is of the form $y = kx$, where $k$ is the constant of variation. Given $y = 2$ when $x = \frac{1}{3}$, we solve for $k$: $2 = k \cdot \frac{1}{3}$, which gives $k = 6$. Thus, the equation is $y = 6x$.

If Y Varies Directly as X, Find the Direct Variation y=2 when x=13y = 2 \text { when } x = \frac { 1 } { 3 }y=2 when x=31​

If Y Varies Directly as X, Find the Direct Variation $y = 2 \text { when } x = \frac { 1 } { 3 }$