If y varies inversely as x, find the inverse variation equation for the situation.
-$y = 45 \text { when } x = \frac { 1 } { 9 }$
A) $y = \frac { x } { 5 }$
B) $y = \frac { 5 } { x }$
C) $y = \frac { 1 } { 5 x }$
D) $y = 405 x$

Question

Quizplus · Accepted Answer

The inverse variation equation is of the form $y = \frac{k}{x}$, where $k$ is the constant of variation. Given $y = 45$ when $x = \frac{1}{9}$, we find $k$ by substituting these values into the equation: $45 = \frac{k}{\frac{1}{9}}$, which simplifies to $k = 5$. Therefore, the equation is $y = \frac{5}{x}$.

If Y Varies Inversely as X, Find the Inverse Variation y=45 when x=19y = 45 \text { when } x = \frac { 1 } { 9 }y=45 when x=91​

If Y Varies Inversely as X, Find the Inverse Variation $y = 45 \text { when } x = \frac { 1 } { 9 }$