If y varies inversely as x, find the inverse variation equation for the situation.
-$y = \frac { 1 } { 9 } \text { when } x = 18$
A) $y = \frac { 1 } { 2 x }$
B) $y = \frac { x } { 2 }$
C) $y = \frac { 2 } { x }$
D) $y = \frac { 1 } { 162 } x$

Question

Quizplus · Accepted Answer

In inverse variation, $y = \frac{k}{x}$. Given $y = \frac{1}{9}$ when $x = 18$, solve for $k$: $\frac{1}{9} = \frac{k}{18}$, so $k = 2$. Thus, the equation is $y = \frac{2}{x}$.

If Y Varies Inversely as X, Find the Inverse Variation y=19 when x=18y = \frac { 1 } { 9 } \text { when } x = 18y=91​ when x=18

If Y Varies Inversely as X, Find the Inverse Variation $y = \frac { 1 } { 9 } \text { when } x = 18$