Sketch the graph of the equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center and
radius.
-$x^{2}+y^{2}-12 x-2 y+33=0$

A) center $( - 6 , - 1 )$; radius $= 2$
B) center $( - 6,1 )$; radius $= 2$
C) center $( 6,1 )$; radius $= 2$
D) center $( 6 , - 1 )$; radius $= 2$

Question

Sketch the graph of the equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center and
radius.
-$x^{2}+y^{2}-12 x-2 y+33=0$

A) center $( - 6 , - 1 )$; radius $= 2$ 
B) center $( - 6,1 )$; radius $= 2$ 
C) center $( 6,1 )$; radius $= 2$ 
D) center $( 6 , - 1 )$; radius $= 2$

Quizplus · Accepted Answer

The Answer of Sketch the graph of the equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center and
radius.
-$x^{2}+y^{2}-12 x-2 y+33=0$

A) center $( - 6 , - 1 )$; radius $= 2$ 
B) center $( - 6,1 )$; radius $= 2$ 
C) center $( 6,1 )$; radius $= 2$ 
D) center $( 6 , - 1 )$; radius $= 2$

Sketch the Graph of the Equation x2+y2−12x−2y+33=0x^{2}+y^{2}-12 x-2 y+33=0x2+y2−12x−2y+33=0 A) Center (−6,−1)( - 6 , - 1 )(−6,−1)

Sketch the Graph of the Equation $x^{2}+y^{2}-12 x-2 y+33=0$ A) Center $( - 6 , - 1 )$