For the given one-to-one function f, find the following.
-$f ( x ) = \sqrt { 4 x - 3 } - 3$
Find $f ( 3 )$ and $f ^ { - 1 } ( 0 )$.
A) $f ( 3 ) = 0 ; f ^ { - 1 } ( 0 ) = 3$
B) $f ( 3 ) = \frac { 9 } { 4 } ; f ^ { - 1 } ( 0 ) = 0$
C) $f ( 3 ) = 9 ; f ^ { - 1 } ( 0 ) = 3$
D) $f ( 3 ) = 3 ; \mathrm { f } ^ { - 1 } ( 0 ) = 0$

Question

Quizplus · Accepted Answer

$f(3) = \sqrt{4(3) - 3} - 3 = \sqrt{9} - 3 = 3 - 3 = 0$. To find $f^{-1}(0)$, set $f(x) = 0$: $0 = \sqrt{4x - 3} - 3$, solving gives $x = 3$.

For the Given One-To-One Function F, Find the Following f(x)=4x−3−3f ( x ) = \sqrt { 4 x - 3 } - 3f(x)=4x−3​−3

For the Given One-To-One Function F, Find the Following $f ( x ) = \sqrt { 4 x - 3 } - 3$