Write as a logarithmic equation.
-$17 ^ { 1 / 2 } = \sqrt { 17 }$
A) $\log _ { 1 / 2 } 17 = \sqrt { 17 }$
B) $\log _ { 17 } \frac { 1 } { 2 } = \sqrt { 17 }$
C) $\log _ { 1 / 2 } \sqrt { 17 } = 17$
D) $\log _ { 17 } \sqrt { 17 } = \frac { 1 } { 2 }$

Question

Quizplus · Accepted Answer

The correct logarithmic form of $17^{1/2} = \sqrt{17}$ is $\log_{17} \sqrt{17} = \frac{1}{2}$, which matches the definition of a logarithm: if $b^y = x$, then $\log_b x = y$.

Write as a Logarithmic Equation 171/2=1717 ^ { 1 / 2 } = \sqrt { 17 }171/2=17​

Write as a Logarithmic Equation $17 ^ { 1 / 2 } = \sqrt { 17 }$