Solve the equation. Give an exact solution.
-$3 ^ { x + 6 } = 2$
A) $\frac { \log 2 } { \log 3 } - 6$

B) $\frac { \log 3 } { \log 2 } + \log 6$

C) $\log 2 - \log 3 - \log 6$

D) $\frac { \log 3 } { \log 2 } + 6$

Question

Solve the equation. Give an exact solution.
-$3 ^ { x + 6 } = 2$
A) $\frac { \log 2 } { \log 3 } - 6$

B) $\frac { \log 3 } { \log 2 } + \log 6$

C) $\log 2 - \log 3 - \log 6$

D) $\frac { \log 3 } { \log 2 } + 6$

Quizplus · Accepted Answer

To solve $3^{x+6} = 2$, take the logarithm of both sides to get $x+6 = \frac{\log 2}{\log 3}$, then solve for $x$ to get $x = \frac{\log 2}{\log 3} - 6$.

Solve the Equation 3x+6=23 ^ { x + 6 } = 23x+6=2

Solve the Equation $3 ^ { x + 6 } = 2$