Use the quadratic formula to solve the equation.
-$\frac { x ^ { 2 } } { 16 } + x + \frac { 41 } { 16 } = 0$
A) $8 - \sqrt { 41 } , 8 + \sqrt { 41 }$
B) $8 + \sqrt { 23 }$
C) $- 16 + \sqrt { 41 }$
D) $- 8 - \sqrt { 23 } , - 8 + \sqrt { 23 }$

Question

Quizplus · Accepted Answer

The quadratic formula is $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$. For the given equation, $a = \frac{1}{16}$, $b = 1$, and $c = \frac{41}{16}$. Substituting these values into the formula gives $x = \frac{-1 \pm \sqrt{1^2 - 4(\frac{1}{16})(\frac{41}{16})}}{2(\frac{1}{16})}$, which simplifies to $x = -8 \pm \sqrt{23}$, corresponding to choice D.

Use the Quadratic Formula to Solve the Equation x216+x+4116=0\frac { x ^ { 2 } } { 16 } + x + \frac { 41 } { 16 } = 016x2​+x+1641​=0

Use the Quadratic Formula to Solve the Equation $\frac { x ^ { 2 } } { 16 } + x + \frac { 41 } { 16 } = 0$