Solve.
-$x = 8 + 2 \sqrt { x }$
A) 16
B) 32
C) 8
D) 12

Question

Quizplus · Accepted Answer

To solve the equation $x = 8 + 2 \sqrt { x }$, we can rearrange it to isolate the square root term: $2 \sqrt { x } = x - 8$. Squaring both sides to eliminate the square root gives $4x = x^2 - 16x + 64$. Rearranging to form a quadratic equation, we get $x^2 - 20x + 64 = 0$. Factoring or using the quadratic formula, we find that $x = 16$ or $x = 4$. However, substituting $x = 4$ back into the original equation shows it doesn't satisfy the equation, leaving $x = 16$ as the correct solution.

Solve - x=8+2xx = 8 + 2 \sqrt { x }x=8+2x​

Solve
- $x = 8 + 2 \sqrt { x }$