Solve the problem.
-The perimeter of a rectangle is 54 m. If the width were doubled and the length were increased by 15 m, the perimeter would be 98 m. What are the length and width of the rectangle?
A)width 8 m, length 13 m
B)width 7 m, length 20 m
C)width 13 m, length 13 m
D)width 20 m, length 7 m

Question

Quizplus · Accepted Answer

The original perimeter equation is 2(l + w) = 54, leading to l + w = 27. The modified perimeter equation is 2(2w + l + 15) = 98, leading to 2w + l + 15 = 49. Solving these equations gives width = 7 m and length = 20 m.

Solve the Problem. -The Perimeter of a Rectangle Is 54 M. If the M