Factor by grouping.
-$$x ^ { 3 } + 6 x ^ { 2 } + 8 x + 48$$
A) $( x + 6 ) \left( x ^ { 2 } + 8 \right)$
B) $( x + 6 ) \left( x ^ { 2 } - 8 \right)$
C) $( x - 6 ) \left( x ^ { 3 } + 8 \right)$
D) $( x + 6 x ) \left( x ^ { 2 } + 8 \right)$

Question

Quizplus · Accepted Answer

To factor by grouping, we first split the expression into two groups: $x^3 + 6x^2$ and $8x + 48$. Factoring out the greatest common factor from each group gives us $x^2(x + 6) + 8(x + 6)$. We can then factor out the common factor $(x + 6)$, resulting in $(x + 6)(x^2 + 8)$.

Factor by Grouping x3+6x2+8x+48x ^ { 3 } + 6 x ^ { 2 } + 8 x + 48x3+6x2+8x+48

Factor by Grouping $x ^ { 3 } + 6 x ^ { 2 } + 8 x + 48$