Factor.
-$20 x ^ { 2 } + 31 x y + 12 y ^ { 2 }$
A) $( 20 x + 3 y ) ( x + 4 y )$
B) $( 4 x + 3 y ) ( 5 x + 4 y )$
C) $( 4 x - 3 y ) ( 5 x - 4 y )$
D) $( 20 x + y ) ( x + 12 y )$

Question

Quizplus · Accepted Answer

The correct factorization of $20x^2 + 31xy + 12y^2$ is $(4x + 3y)(5x + 4y)$, as multiplying these two factors together using the FOIL method (First, Outer, Inner, Last) gives the original quadratic expression.

Factor - 20x2+31xy+12y220 x ^ { 2 } + 31 x y + 12 y ^ { 2 }20x2+31xy+12y2

Factor
- $20 x ^ { 2 } + 31 x y + 12 y ^ { 2 }$