Factor by grouping.
-$$s ^ { 2 } + 4 s + 2 s + 8$$
A) $s ( s + 14 )$
B) $( s + 4 ) ( s - 2 )$
C) $( s - 4 ) ( s - 2 )$
D) $( \mathrm { s } + 4 ) ( \mathrm { s } + 2 )$

Question

Quizplus · Accepted Answer

First, group the terms: $s^2 + 4s + 2s + 8$. Factoring by grouping, we get $s(s + 4) + 2(s + 4)$. Factoring out the common factor $(s + 4)$, we get $(s + 4)(s + 2)$.

Factor by Grouping s2+4s+2s+8s ^ { 2 } + 4 s + 2 s + 8s2+4s+2s+8

Factor by Grouping $s ^ { 2 } + 4 s + 2 s + 8$