Solve.
-$a + b = s + r$ for $s$
A) $s = \frac { a } { r } + b$
B) $s = r ( a + b )$
C) $s = \frac { a + b } { r }$
D) $s = a + b - r$

Name: Solve. -$a + b = s + r$ for $s$ A) $s = \frac { a } { r } + b$ B) $s = r ( a + b )$ C) $s = \frac { a + b } { r }$ D) $s = a + b - r$
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Question

Quizplus · Accepted Answer

To solve for $s$, we isolate $s$ on one side of the equation: $s = a + b - r$. This is achieved by subtracting $r$ from both sides of the equation $a + b = s + r$.

Solve - a+b=s+ra + b = s + ra+b=s+r For sss A) s=ar+bs = \frac { a } { r } + bs=ra​+b

Solve
- $a + b = s + r$ For $s$ A) $s = \frac { a } { r } + b$