Solve the Problem $2.9$ Hours If the Formula $\mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { t / 2.9 }$

Solve the problem.
-The half-life of Antimony 111 is $2.9$ hours. If the formula $\mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { t / 2.9 }$ gives the percent (as a decimal) remaining after time $t$ (in hours) , sketch P versus $t$ .

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