Solve by completing the square.
-$$x ^ { 2 } + 4 x = 3$$
A) $- 2 \pm 2 \sqrt { 7 }$
B) $- 1 \pm \sqrt { 7 }$
C) $- 2 \pm \sqrt { 7 }$
D) $2 + \sqrt { 7 }$

Name: Solve by completing the square. -\[x ^ { 2 } + 4 x = 3\] A) $- 2 \pm 2 \sqrt { 7 }$ B) $- 1 \pm \sqrt { 7 }$ C) $- 2 \pm \sqrt { 7 }$ D) $2 + \sqrt { 7 }$
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Question

Quizplus · Accepted Answer

To complete the square, rewrite the equation as $x^2 + 4x + 4 = 3 + 4$, which simplifies to $(x + 2)^2 = 7$. Solving for $x$ gives $x + 2 = \pm \sqrt{7}$, so $x = -2 \pm \sqrt{7}$.

Solve by Completing the Square x2+4x=3x ^ { 2 } + 4 x = 3x2+4x=3

Solve by Completing the Square $x ^ { 2 } + 4 x = 3$