Solve the problem. Give the answer to the nearest tenth.
-The position of an object moving in a straight line is given by $s = 2 t ^ { 2 } - 3 t$, where $s$ is in meters and $t$ is the time in seconds the object has been in motion. How long (to the nearest tenth) will it take the object to move 19 meters?
A) $3.9 \mathrm { sec }$
B) $3.7 \mathrm { sec }$
C) $20.0 \mathrm { sec }$
D) $66.5 \mathrm { sec }$

Question

Quizplus · Accepted Answer

To find the time it takes for the object to move 19 meters, set $s = 19$ and solve for $t$: $19 = 2t^2 - 3t$. Rearranging gives $2t^2 - 3t - 19 = 0$. Solving this quadratic equation for $t$ yields $t \approx 3.9$ seconds.

Solve the Problem s=2t2−3ts = 2 t ^ { 2 } - 3 ts=2t2−3t

Solve the Problem $s = 2 t ^ { 2 } - 3 t$