Solve. Round results to the nearest thousandth.
-$$x ^ { 2 } + 10 x - 19 = 0$$
A) $1.633 , - 11.633$
B) $11.633 , - 1.633$
C) $13.958 , - 3.958$
D) $3.958 , - 13.958$

Question

Quizplus · Accepted Answer

This quadratic equation can be solved using the quadratic formula, $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 1$, $b = 10$, and $c = -19$. Plugging these values in gives $x = \frac{-10 \pm \sqrt{10^2 - 4(1)(-19)}}{2(1)} = \frac{-10 \pm \sqrt{100 + 76}}{2} = \frac{-10 \pm \sqrt{176}}{2} = \frac{-10 \pm 13.266}{2}$, which results in $x = 1.633$ and $x = -11.633$, rounded to the nearest thousandth.

Solve Round Results to the Nearest Thousandth x2+10x−19=0x ^ { 2 } + 10 x - 19 = 0x2+10x−19=0

Solve Round Results to the Nearest Thousandth $x ^ { 2 } + 10 x - 19 = 0$