The amount of radioactive carbon-14 in an archaeological specimen is given by $C = C _ { 0 } e ^ { - 0.000121 t }$ where $C _ { 0 }$ is the original amount, and t is the number of years after the specimen died. How many years would it take for the carbon-14 remaining to be 80% of the original amount? Round to the
nearest year.

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The Answer of The amount of radioactive carbon-14 in an archaeological specimen is given by $C = C _ { 0 } e ^ { - 0.000121 t }$ where $C _ { 0 }$ is the original amount, and t is the number of years after the specimen died. How many years would it take for the carbon-14 remaining to be 80% of the original amount? Round to the
nearest year.

The Amount of Radioactive Carbon-14 in an Archaeological Specimen Is C=C0e−0.000121tC = C _ { 0 } e ^ { - 0.000121 t }C=C0​e−0.000121t

The Amount of Radioactive Carbon-14 in an Archaeological Specimen Is $C = C _ { 0 } e ^ { - 0.000121 t }$