The temperature at an Ohio state park for one day in June can be approximated by the function $T ( x ) = 0.284 x ^ { 2 } - 5.11 x + 82 \quad 0 \leq x \leq 18$ where T is degrees Fahrenheit and x is the number of hours after 5 PM on Friday. T(x) has no x-intercepts. Explain why this makes sense in the context of the problem.

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The Answer of The temperature at an Ohio state park for one day in June can be approximated by the function $T ( x ) = 0.284 x ^ { 2 } - 5.11 x + 82 \quad 0 \leq x \leq 18$ where T is degrees Fahrenheit and x is the number of hours after 5 PM on Friday. T(x) has no x-intercepts. Explain why this makes sense in the context of the problem.

The Temperature at an Ohio State Park for One Day T(x)=0.284x2−5.11x+820≤x≤18T ( x ) = 0.284 x ^ { 2 } - 5.11 x + 82 \quad 0 \leq x \leq 18T(x)=0.284x2−5.11x+820≤x≤18

The Temperature at an Ohio State Park for One Day $T ( x ) = 0.284 x ^ { 2 } - 5.11 x + 82 \quad 0 \leq x \leq 18$