Solve by using either the addition method or the substitution method. $$\begin{array} { l }
0.03 x = 0.04 y + 0.2 \
- 0.05 y = - 4.4 + 0.04 x
\end{array}$$
A) (40, 30)
B) (70, 60)
C) (70, 30)
D) (60, 40)

Question

Solve by using either the addition method or the substitution method. $$\begin{array} { l } 
0.03 x = 0.04 y + 0.2 \
- 0.05 y = - 4.4 + 0.04 x
\end{array}$$
A) (40, 30)
B) (70, 60)
C) (70, 30)
D) (60, 40)

Quizplus · Accepted Answer

The Answer of Solve by using either the addition method or the substitution method. $$\begin{array} { l } 
0.03 x = 0.04 y + 0.2 \
- 0.05 y = - 4.4 + 0.04 x
\end{array}$$
A) (40, 30)
B) (70, 60)
C) (70, 30)
D) (60, 40)

Solve by Using Either the Addition Method or the Substitution 0.03x=0.04y+0.2−0.05y=−4.4+0.04x\begin{array} { l } 0.03 x = 0.04 y + 0.2 \\- 0.05 y = - 4.4 + 0.04 x\end{array}0.03x=0.04y+0.2−0.05y=−4.4+0.04x​

Solve by Using Either the Addition Method or the Substitution $\begin{array} { l } 0.03 x = 0.04 y + 0.2 \\- 0.05 y = - 4.4 + 0.04 x\end{array}$