Find the sum. $$\sum _ { j = 1 } ^ { 6 } \frac { j + 3 } { j }$$
A) $\frac { 267 } { 20 }$
B) 39
C) $\frac { 13 } { 2 }$
D) $\frac { 167 } { 20 }$

Question

Find the sum. $$\sum _ { j = 1 } ^ { 6 } \frac { j + 3 } { j }$$ 
A) $\frac { 267 } { 20 }$
B) 39
C) $\frac { 13 } { 2 }$
D) $\frac { 167 } { 20 }$

Quizplus · Accepted Answer

To find the sum, calculate each term individually and then add them together: $$\sum _ { j = 1 } ^ { 6 } \frac { j + 3 } { j } = \frac { 1 + 3 } { 1 } + \frac { 2 + 3 } { 2 } + \frac { 3 + 3 } { 3 } + \frac { 4 + 3 } { 4 } + \frac { 5 + 3 } { 5 } + \frac { 6 + 3 } { 6 }$$ Simplifying each term gives: $$4 + \frac{5}{2} + 2 + \frac{7}{4} + \frac{8}{5} + \frac{9}{6}$$ Adding these together gives $\frac { 267 } { 20 }$.

Find the Sum ∑j=16j+3j\sum _ { j = 1 } ^ { 6 } \frac { j + 3 } { j }j=1∑6​jj+3​

Find the Sum $\sum _ { j = 1 } ^ { 6 } \frac { j + 3 } { j }$