The model $$\sqrt { \hat { \text { distance } } } = 3.30 + 0.235 ( \text { speed } )$$ ) can be used to predict the stopping distance (in feet) for a
Car traveling at a specific speed (in mph). According to this model, about how much distance will a
Car going 65 mph need to stop?
A) 27.0 feet
B) 18.6 feet
C) 729.0 feet
D) 4.3 feet
E) 345.0 feet

Question

The model $$\sqrt { \hat { \text { distance } }  } = 3.30 + 0.235 ( \text { speed } )$$ ) can be used to predict the stopping distance (in feet) for a
Car traveling at a specific speed (in mph). According to this model, about how much distance will a
Car going 65 mph need to stop?
A) 27.0 feet
B) 18.6 feet
C) 729.0 feet
D) 4.3 feet
E) 345.0 feet

Quizplus · Accepted Answer

The correct answer is E.The model is:$$\sqrt { \hat { 	ext { distance } }  } = 3.30 + 0.235 ( 	ext { speed } )$$To find the stopping distance for a car going 65 mph, we plug in 65 for speed:$$\sqrt { \hat { 	ext { distance } }  } = 3.30 + 0.235 ( 65 ) = 18.6$$Squaring both sides, we get:$$\hat { 	ext { distance } }  = 18.6^2 = 345.0$$So the car will need about 345.0 feet to stop.

The Model distance ^=3.30+0.235( speed )\sqrt { \hat { \text { distance } } } = 3.30 + 0.235 ( \text { speed } ) distance ^​=3.30+0.235( speed )

The Model $\sqrt { \hat { \text { distance } } } = 3.30 + 0.235 ( \text { speed } )$