What magnitude net force is required to accelerate a 1200-kg car uniformly from 0 m/s to 27.0 m/s in 10.0 s?
A) 3240 N
B) 11800 N
C) 4360 N
D) 1620 N
E) 444 N

Question

Quizplus · Accepted Answer

The net force required can be calculated using Newton's second law, $F = ma$, where $m$ is the mass and $a$ is the acceleration. First, find the acceleration using the formula $a = \frac{\Delta v}{\Delta t}$, where $\Delta v = 27.0 \, \text{m/s} - 0 \, \text{m/s} = 27.0 \, \text{m/s}$ and $\Delta t = 10.0 \, \text{s}$. So, $a = \frac{27.0 \, \text{m/s}}{10.0 \, \text{s}} = 2.7 \, \text{m/s}^2$. Then, $F = (1200 \, \text{kg})(2.7 \, \text{m/s}^2) = 3240 \, \text{N}$.

What Magnitude Net Force Is Required to Accelerate a 1200-Kg