The half-life of radon-222 is $3.83 \mathrm {~d}$. If a sample of radon initially contains $6.00 \times 10 ^ { 8 }$ radon atoms, how many of them are left after $10.0 \mathrm {~d}$ ?

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The number of radon atoms left after a certain time can be calculated using the formula $N = N_0 \times (1/2)^{t/T}$, where $N$ is the final amount, $N_0$ is the initial amount, $t$ is the time elapsed, and $T$ is the half-life. Plugging in the given values, $N = 6.00 \times 10^8 \times (1/2)^{10.0/3.83}$, we find that the number of atoms left is approximately $9.82 \times 10^7$.

The Half-Life of Radon-222 Is 3.83 d3.83 \mathrm {~d}3.83 d If a Sample of Radon Initially Contains

The Half-Life of Radon-222 Is $3.83 \mathrm {~d}$ If a Sample of Radon Initially Contains