What is the momentum of a photon of light that has a wavelength of $480 \mathrm {~nm}$ ?
$$\left( h = 6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s } \right)$$
A) $1.1 \times 10 ^ { - 27 } \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }$
B) $1.4 \times 10 ^ { - 27 } \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }$
C) $2.0 \times 10 ^{- 27} \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }$
D) $2.2 \times 10 ^{- 27 }\mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }$
E) $1.8 \times 10 ^ { - 27 } \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }$

Question

Quizplus · Accepted Answer

The momentum $p$ of a photon can be calculated using the formula $p = \frac{h}{\lambda}$, where $h$ is Planck's constant and $\lambda$ is the wavelength of the photon. Substituting the given values, $p = \frac{6.626 \times 10^{-34} \mathrm{Js}}{480 \times 10^{-9} \mathrm{m}} = 1.38 \times 10^{-27} \mathrm{kg \cdot m/s}$, which rounds to $1.4 \times 10^{-27} \mathrm{kg \cdot m/s}$.

What Is the Momentum of a Photon of Light That 480 nm480 \mathrm {~nm}480 nm

What Is the Momentum of a Photon of Light That $480 \mathrm {~nm}$