An aluminum electric tea kettle with a mass of 500 g is heated with a 500 -W heating coil. How Iong will it take to heat up 1.0 kg of water from $18 ^ { \circ } \mathrm { C } \text { to } 98 ^ { \circ } \mathrm { C }$ in the tea kettle? The specific heat of aluminum is 900 $\mathrm { J } / \mathrm { kg } \cdot \mathrm { K }$ and that of water is 4186 $\mathrm { J } / \mathrm { kg } \cdot \mathrm { K } .$

Question

An aluminum electric tea kettle with a mass of  500 g is heated with a 500 -W heating coil. How Iong will it take to heat up  1.0 kg of water from $18 ^ { \circ } \mathrm { C } \text { to } 98 ^ { \circ } \mathrm { C }$ in the tea kettle? The specific heat of aluminum is 900 $\mathrm { J } / \mathrm { kg } \cdot \mathrm { K }$ and that of water is 4186 $\mathrm { J } / \mathrm { kg } \cdot \mathrm { K } .$

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The Answer of An aluminum electric tea kettle with a mass of  500 g is heated with a 500 -W heating coil. How Iong will it take to heat up  1.0 kg of water from $18 ^ { \circ } \mathrm { C } \text { to } 98 ^ { \circ } \mathrm { C }$ in the tea kettle? The specific heat of aluminum is 900 $\mathrm { J } / \mathrm { kg } \cdot \mathrm { K }$ and that of water is 4186 $\mathrm { J } / \mathrm { kg } \cdot \mathrm { K } .$

An Aluminum Electric Tea Kettle with a Mass of 18∘C to 98∘C18 ^ { \circ } \mathrm { C } \text { to } 98 ^ { \circ } \mathrm { C }18∘C to 98∘C

An Aluminum Electric Tea Kettle with a Mass of $18 ^ { \circ } \mathrm { C } \text { to } 98 ^ { \circ } \mathrm { C }$