Solve the problem.
-A rotating beacon is located a distance $d$ from a long wall. The distance $d$ is given by $\mathrm { d } = 4 \tan 2 \pi \mathrm { t }$,
where $t$ is the time measured in seconds since the beacon started rotating. Solve the equation for $t$.
A) $\mathrm { t } = \frac { 1 } { 2 \pi } \arctan \frac { \mathrm { d } } { 4 }$
B) $t = 2 \pi \tan \frac { d } { 4 }$
C) $\mathrm { t } = \frac { 1 } { 2 \pi } \tan \frac { \mathrm { d } } { 4 }$
D) $\mathrm { t } = 2 \pi \arctan \frac { \mathrm { d } } { 4 }$

Question

Quizplus · Accepted Answer

To solve for $t$, we isolate $t$ on one side of the equation: $d = 4 \tan 2 \pi t$. Taking the inverse tangent ($\arctan$) of both sides and then dividing by $2\pi$ gives $t = \frac{1}{2\pi} \arctan \frac{d}{4}$.

Solve the Problem ddd From a Long Wall ddd Is Given By d=4tan⁡2πt\mathrm { d } = 4 \tan 2 \pi \mathrm { t }d=4tan2πt

Solve the Problem $d$ From a Long Wall $d$ Is Given By $\mathrm { d } = 4 \tan 2 \pi \mathrm { t }$