Solve the equation for exact solutions over the interval [0, 2 $$[ 0,2 \pi ) .$$
-$\cos ^ { 2 } x + 2 \cos x + 1 = 0$
A) $\left\{ \frac { \pi } { 4 } , \frac { 7 \pi } { 4 } \right\}$
B) $\left\{ \frac { \pi } { 2 } , \frac { 3 \pi } { 2 } \right\}$
C) $\{ \pi \}$
D) $\{ 2 \pi \}$

Question

Quizplus · Accepted Answer

The equation can be rewritten as $(\cos x + 1)^2 = 0$, which implies $\cos x = -1$. The solution for $\cos x = -1$ in the interval $[0, 2\pi)$ is $x = \pi$.

Solve the Equation for Exact Solutions Over the Interval [0 [0,2π).[ 0,2 \pi ) .[0,2π).

Solve the Equation for Exact Solutions Over the Interval [0 $[ 0,2 \pi ) .$