Solve the equation for solutions in the interval [0°, 360°). Round to the nearest degree.
-sin 2ϴ = cos ϴ
A){0°, 120°, 180°, 240°}
B){105°, 165°, 285°, 345°}
C){15°, 165°, 195°, 345°}
D){30°, 90°, 150°, 270°}

Question

Quizplus · Accepted Answer

The Answer of Solve the equation for solutions in the interval [0°, 360°). Round to the nearest degree.
-sin 2ϴ = cos ϴ
A){0°, 120°, 180°, 240°}
B){105°, 165°, 285°, 345°}
C){15°, 165°, 195°, 345°}
D){30°, 90°, 150°, 270°}

Solve the Equation for Solutions in the Interval [0°, 360°)