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Solve the Problem dft\mathrm { d } \mathrm { ft }

Question 137

Multiple Choice

Solve the problem.
-It can be shown that if the angle of elevation from an observer to the top of an object is A and the angle of elevation dft\mathrm { d } \mathrm { ft } closer is B\mathrm { B } , then the distance from the object to the closest point of observation is given by
D=dcotBcotAcotBft\mathrm { D } = \frac { \mathrm { d } \cot \mathrm { B } } { \cot \mathrm { A } - \cot \mathrm { B } } \mathrm { ft } \text {. }
Find BB if D=20ft,d=30ftD = 20 \mathrm { ft } , \mathrm { d } = 30 \mathrm { ft } , and A=51A = 51 ^ { \circ } . Give your answer in degrees to the nearest hundredth.


A) 51.0051.00 ^ { \circ }
B) 64.0964.09 ^ { \circ }
C) 72.0572.05 ^ { \circ }
D) 61.6461.64 ^ { \circ }

Correct Answer:

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