Solve the equation for solutions in the interval [0°, 360°). Round to the nearest degree.
-sin 2ϴ + cos 2ϴ = 1
A){0°, 90°, 180°, 270°}
B){0°, 45°, 180°, 225°}
C){0°}
D){33°, 57°, 123°, 147°, 213°, 237°, 303°}

Question

Quizplus · Accepted Answer

The Answer of Solve the equation for solutions in the interval [0°, 360°). Round to the nearest degree.
-sin 2ϴ + cos 2ϴ = 1
A){0°, 90°, 180°, 270°}
B){0°, 45°, 180°, 225°}
C){0°}
D){33°, 57°, 123°, 147°, 213°, 237°, 303°}

Solve the Equation for Solutions in the Interval [0°, 360°)