Find the exact value of s in the given interval that has the given circular function value.
-$$\left[ \frac { 3 \pi } { 2 } , 2 \pi \right] ; \tan \mathrm { s } = - \frac { \sqrt { 3 } } { 3 }$$
A) $s = \frac { \pi } { 6 }$
B) $s = \frac { 7 \pi } { 4 }$
C) $s = \frac { 11 \pi } { 6 }$
D) $s = \frac { 5 \pi } { 3 }$

Question

Quizplus · Accepted Answer

The tangent function is negative in the fourth quadrant, and $\tan(\frac{11\pi}{6}) = -\frac{\sqrt{3}}{3}$, which is in the given interval $\left[\frac{3\pi}{2}, 2\pi\right]$.

Find the Exact Value of S in the Given Interval [3π2,2π];tan⁡s=−33\left[ \frac { 3 \pi } { 2 } , 2 \pi \right] ; \tan \mathrm { s } = - \frac { \sqrt { 3 } } { 3 }[23π​,2π];tans=−33​​

Find the Exact Value of S in the Given Interval $\left[ \frac { 3 \pi } { 2 } , 2 \pi \right] ; \tan \mathrm { s } = - \frac { \sqrt { 3 } } { 3 }$