The following table describes the results of roadworthiness tests of Ford Focus cars that are three years old (based on data from the Department of Transportation). The random variable x
Represents the number of cars that failed among six that were tested for roadworthiness:
$\begin{array} { | c | c | }
\hline \boldsymbol { x } & \boldsymbol { P } ( \boldsymbol { x } ) \
\hline 0 & 0.377 \
\hline 1 & 0.399 \
\hline 2 & 0.176 \
\hline 3 & 0.041 \
\hline 4 & 0.005 \
\hline 5 & 0 + \
\hline 6 & 0 + \
\hline
\end{array}$
Is the probability of getting three or more cars that fail among six cars tested significant, Determined by a cutoff value of 0.05?
A) Yes
B) No

Question

The following table describes the results of roadworthiness tests of Ford Focus cars that are three years old (based on data from the Department of Transportation). The random variable x
Represents the number of cars that failed among six that were tested for roadworthiness: 
$\begin{array} { | c | c | } 
\hline \boldsymbol { x } & \boldsymbol { P } ( \boldsymbol { x } ) \
\hline 0 & 0.377 \
\hline 1 & 0.399 \
\hline 2 & 0.176 \
\hline 3 & 0.041 \
\hline 4 & 0.005 \
\hline 5 & 0 + \
\hline 6 & 0 + \
\hline
\end{array}$
 Is the probability of getting three or more cars that fail among six cars tested significant, Determined by a cutoff value of 0.05?
A) Yes
B) No

Quizplus · Accepted Answer

The probability of getting three or more cars that fail is the sum of probabilities for x = 3, 4, 5, and 6, which is 0.041 + 0.005 + 0 + 0 = 0.046. Since 0.046 is less than the cutoff value of 0.05, it is considered significant.

The Following Table Describes the Results of Roadworthiness Tests of Ford