The coil in a 60-Hz ac generator has an area of 3.0 × 10^-2 m² and is rotated in a 0.12 T magnetic field. The coil has 125 turns. What is the peak output voltage of this generator?

Question

Quizplus · Accepted Answer

The peak output voltage (emf) of an AC generator is given by the formula: E_peak = NABωsin(ωt), where N is the number of turns, A is the area, B is the magnetic field, and ω is the angular frequency (ω = 2πf). For a 60-Hz generator, ω = 2π(60). Substituting the given values: E_peak = 125 * 3.0 × 10^-2 * 0.12 * 2π * 60 = 170 V.

The Coil in a 60-Hz Ac Generator Has an Area