A piece of wood 350 mm × 350 mm and 15 mm thick conducts heat through its thickness under steady state conditions. The rate of heat flow is measured to be 14.0 watts when the temperature difference is 28 C°. Determine the coefficient of thermal conductivity for this wood

Question

Quizplus · Accepted Answer

The coefficient of thermal conductivity (k) can be calculated using the formula: k = (Q * L) / (A * ΔT), where Q is the heat flow rate, L is the thickness, A is the area, and ΔT is the temperature difference. Substituting the given values: k = (14 W * 0.015 m) / (0.35 m * 0.35 m * 28 C°) = 0.061 J/(m∙s∙C°).

A Piece of Wood 350 Mm × 350 Mm and 15