A board that is 20.0 cm wide, 5.00 cm thick, and 3.00 m long has a density 400 kg/m³. The board is floating partially submerged in water. What minimum mass would need to be set on the board to completely submerge the board?

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The correct answer is A.The volume of the board is 0.0200 m * 0.0500 m * 3.00 m = 0.00300 m^3. The mass of the water displaced by the board is 0.00300 m^3 * 1000 kg/m^3 = 3.00 kg. The mass of the board is 0.00300 m^3 * 400 kg/m^3 = 1.20 kg. The minimum mass that would need to be set on the board to completely submerge the board is 3.00 kg - 1.20 kg = 1.80 kg.

A Board That Is 20