The tensile strength for a certain steel wire is 3000 MN/m². What is the maximum load that can be applied to a wire with a diameter of 3.0 mm made of this kind of steel? A)64 kN B)9.0 kN C)42 kN D)85 kN E)21 kN

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Quizplus · Accepted Answer

The maximum load is calculated using the formula: Load = Tensile Strength × Cross-sectional Area. The area for a wire with a diameter of 3.0 mm is π(1.5 mm)^2 = 7.07 mm² = 7.07 × 10^-6 m². Thus, the maximum load is 3000 MN/m² × 7.07 × 10^-6 m² = 21.21 kN, approximately 21 kN.

The Tensile Strength for a Certain Steel Wire Is 3000